How To Get List Of Dict Instead Of Using Collection.defaultdict In Python

I am trying to convert a list into nested dictionaries recursively as following :- Given Input :- parse_list = ['A','B','C','D'] Required Output :- data = [ {'name': 'A',

Solution 1:

You can acheive it simply like this

parse_list = ['A','B','C','D']

dicton={}

for i in reversed(parse_list):
    dicton['child']=[dicton]
    dicton['name']=i


print dicton
#output {'name': 'A', 
         'child': [{'name': 'B', 
                     'child': [{'name': 'C', 
                                'child': [{'name': 'D', 
                                            'child': [{}]
                                                         }]}]}]}

Solution 2:

In a recursive way

parse_list = ['A','B','C','D']



def createdict(l, d):
    if len(l) == 0:
        return None
    d = dict()
    d['name'] = l[0]
    d['childs'] = [createdict(l[1:], d)]
    return d

resultDict = createdict(parse_list, dict())

Solution 3:

Here's a recursive solution

parse_list = ['A','B','C','D']

def descend(l):
    if l:
        return [{'name': l[0],
                'childs': descend(l[1:])}]
    else:
        return None

data = descend(parse_list)