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Cannot Parse The Date In Python

I need to parse date and time. Here is what I've got: import time a = time.strptime('Apr 28 2013 23:01', '%b %d %y %H:%M') print a But it gives me Traceback (most recent call las

Solution 1:

%y should be %Y for a 4 digit year...

From the docs:

%y  Yearwithout century as a decimal number [00,99].    
%Y  Yearwith century as a decimal number.

Solution 2:

You can

import time
a = time.strptime('Apr 28 2013 23:01', "%b %d %Y %H:%M")
print time.strftime("%d/%m/%Y",a)

with Y. It is followed by a conversion line of code, and gives result

28/04/2013

Solution 3:

Jon's answer is of course correct, but as you noticed these things can be difficult to find.

As a general suggestion for debugging strptime problems I recommend printing out a known datetime using the format string you use for parsing:

from datetime import datetime

d = datetime(2013, 4, 28, 23, 1)
print d.strftime("%b %d %y %H:%M")
print'Apr 28 2013 23:01'

A visual comparison of the output lines:

Apr281323:01Apr282013 23:01

quickly finds the problem and also works when your format string is correct, but you are working with a different locale (e.g. in Spanish where it would expect 'Abr' instead of 'Apr')

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