Xml Value Replacement In Python

Question

For the following sample.xml file, how do I replace the value of arg key 'Type A' and 'Type B' separately using Python? sample.xml:

Solution 1:

You can check the "key" == 'Type A' / 'Type B' by using get method, like this:

for node in tree.iterfind('.//logging/Adapter[@type="abcdef"]'):
    for child in node:
        # check if the key is'Type A'if child.get('key') == 'Type A':
            child.set('value', 'false')
        # ... if'Type B' ...

In fact, you can improve your code by using a better xpath accessing directly:

for node in tree.iterfind('.//logging/Adapter[@type="abcdef"]/arg'):
    # so you don't need another inner loop to access <arg> elementsif node.get('key') == 'Type A':
        node.set('value', 'false')
    # ... if 'Type B' ...

Solution 2:

Used lxml.etree for parsing HTML content and xpath method to get target arg tag which key attribute value is Type A

Code:

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from lxml import etree
root = etree.fromstring(content)
for i in root.xpath('//Adapter[@type="abcdef"]/arg[@key="Type A"]'):
    i.attrib["value"] = "false"print etree.tostring(root)

Output:

python test.py 
<sample><Adaptertype="abcdef"><argkey="Type A"value="false"/><argkey="Type B"value="true"/></Adapter></sample>

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Xml Value Replacement In Python

Solution 1:

Solution 2:

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