How To Accept The Input Of Both Int And Float Types?

I am making a currency converter. How do I get python to accept both integer and float? This is how I did it: def aud_brl(amount,From,to): ER = 0.42108 if amount == int:

Solution 1:

I'm really hoping I'm not completely misunderstanding the question but here I go.

It looks like you just want to make sure the value passed in can be operated upon like a float, regardless of whether the input is 3 or 4.79 for example, correct? If that's the case, then just cast the input as a float before operating on it. Here's your modified code:

def aud_brl(amount, From, to):
    ER = 0.42108 
    if From.strip() == 'aud' and to.strip() == 'brl': 
        result = amount/ER 
    elif From.strip() == 'brl' and to.strip() == 'aud': 
        result = amount*ER 

    print(result)

def question(): 
    amount = float(input("Amount: "))
    From = input("From: ") 
    to = input("To: ")

    if (From == 'aud' or From == 'brl') and (to == 'aud' or to == 'brl'): 
        aud_brl(amount, From, to)

question()

(I made a few changes as well for the sake of neatness, I hope you don't mind <3)

Solution 2:

this is how you could check the given string and accept int or float (and also cast to it; nb will be an int or a float):

number = input("Enter a number: ")

nb = Nonefor cast in (int, float):
    try:
        nb = cast(number)
        print(cast)
        breakexcept ValueError:
        pass

but in your case just using float might do the trick (as also string representations of integers can be converted to floats: float('3') -> 3.0):

number = input("Enter a number: ")

nb = Nonetry:
    nb = float(number)
except ValueError:
    pass

if nb is None you got something that could not be converted to a float.

Solution 3:

Use the isinstance function, which is built in

ifisinstance(num, (int, float)):
    #do stuff

Also, you should refrain from using reserved keywords for variable names. The keyword from is a reserved keyword in Python

Finally, there is one other error I noticed:

ifFrom== 'aud' or 'brl'

Should be

ifFrom== 'aud'orFrom== 'brl'

Lastly, to clean up the if statements you could theoretically use the list (if you have more currencies in the future, this might be better.

currencies = ['aud', 'brl']     #other currencies possibleifFrom in currencies and to in currencies:
    #do conversion

Solution 4:

amount==int doesn't make sense. input gives us a string. int (and float) is a function. A string never equals a function.

In [42]: x=input('test')
test12.23In [43]: x
Out[43]: '12.23'In [44]: int(x)
....
ValueError: invalid literal forint() with base 10: '12.23'In [45]: float(x)
Out[45]: 12.23

float('12.23') returns a float object. int('12.23') produces an error, because it isn't a valid integer string format.

If the user might give either '12' or '12.23', it is safer to use float(x) to convert it to a number. The result will be a float. For many calculations you don't need to worry whether it is a float or integer. The math is the same.

You can convert between int and floats if needed:

In[45]: float(x)
Out[45]: 12.23In[46]: float(12)
Out[46]: 12.0In[47]: int(12.23)
Out[47]: 12In[48]: round(12.23)
Out[48]: 12

You can also do instance tests

In [51]: isinstance(12,float)
Out[51]: False
In [52]: isinstance(12.23,float)
Out[52]: True
In [53]: isinstance(12.23,int)
Out[53]: False
In [54]: isinstance(12,int)
Out[54]: True

But you probably don't need to do any those.

Solution 5:

These seem to work well.

def getInt(): """ input returns a str, coerce return to required type """ x = str() while type(x) != int: try: return int(input('enter an integer: ')) except ValueError: continue

def getFloat(): """ input returns a str, coerce return to required type """ x = str() while type(x) != float: try: return float(input('enter a float: ')) except ValueError: continue