Remove All Namespaces From Xml

Is there a way to remove namespaces from an xml (where I know there aren't any name collisions)? Currently I'm doing this for each known namespace: s = re.sub(r'(<\/?)md:', r'\1

Solution 1:

You can use the XSLT approach by calling the following XSLT-1.0 template from Python. It combines the identity template with a template that transforms the (full) name()s of the elements to their local-name()s only. That means all <ns1:abc> elements are transformed to <abc>, for example. The namespaces are omitted.

However, how useful this is depends on your usecase. It reduces the amount of information, so handle with care.

<?xml version="1.0" encoding="UTF-8"?><xsl:stylesheetversion="1.0"xmlns:xsl="http://www.w3.org/1999/XSL/Transform"><xsl:outputmethod="xml"indent="yes"/><xsl:templatematch="node()|@*"><!-- Identity template copies all nodes (except for elements, which are handled by the other template) --><xsl:copy><xsl:apply-templatesselect="node()|@*" /></xsl:copy></xsl:template><xsl:templatematch="*"><!-- Removes all namespaces from all elements --><xsl:elementname="{local-name()}"><xsl:apply-templatesselect="node()|@*" /></xsl:element></xsl:template></xsl:stylesheet>

Apply it with an XSLT-1.0 (or above) framework/processor.