Elegant Way To Extract A Tuple From List Of Tuples With Minimum Value Of Element

I am having list of tuple from which I want the tuple with the minimum value at index 1. For example, if my list is like: a =[('a', 2), ('ee', 3), ('mm', 4), ('x', 1)] I want the

Solution 1:

You may use min() function with key parameter in order to find the tuple with minimum value in the list. There is no need to sort the list. Hence, your min call should be like:

>>> min(a, key=lambda t: t[1])
('x', 1)

Even better to use operator.itemgetter() instead of lambda expression; as itemgetter are comparatively faster. In this case, the call to min function should be like:

>>>from operator import itemgetter>>>min(a, key=itemgetter(1))
('x', 1)

Note: min() is a in-built function in Python. You should not be using it as a variable name.

Solution 2:

This will also work:

min([x[::-1] for x in a])[::-1]
# ('x', 1)