Django Templates First Element Of A List
I pass a dictionary to my Django Template, Dictionary & Template is like this - lists[listid] = {'name': l.listname, 'docs': l.userdocs.order_by('-id')} {% for k, v in lists
Solution 1:
Solution 2:
You can use the {% with %}
templatetag for this sort of thing.
{% with v.docs|first as first_doc %}{{ first_doc.id }}{% endwith %}
Solution 3:
I don't know if this is helpful..
What you want is the first value of an iterable (v.docs) and you are iterating over another encapsulating iterable (lists).
For the count, I would do the same, but for the first element.. I'd iterate over the v.docs individually and retrieve the first value via an inner loop.
{% for doc in v.docs %}
{% if v.docs | first %}
<li>doc</li>
{% endif %}
{% endfor %}
Note: the first filter is applied to v.docs , not doc. Yeah. It involves another loop :(
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