Why Does Matplotlib's Slider Only Allow A Range Of 0-7?

I am trying to plot the values of a bitwise circular shift on 1 byte. I'd like to have a slider let me change the original input value. I'm using the slider example on the matplotl

Solution 1:

The problem is in the last line plt.axis([-0.5, numrots-1 + 0.5, -2, maxval + 2]) which is acting on the axes that holds the slider, not on the axis with the data.

I would recommend using the OO interface to matplotlib rather than the pyplot interface for anything programmatic. The pyplot interface is good for interactive stuff, but it has a good deal of hidden state.

You also need to return a reference to the slider object due to the way call backs work.

import matplotlib.pyplot as plt
from matplotlib.widgets import Slider

from numpy import uint8
from numpy import uint16
from numpy import uint32
from numpy import uint64

defsizeof(x):
    return2 ** [uint8, uint16, uint32, uint64].index(x)

defrot(x, i):
    returntype(x)((x >> i) | (x << (sizeof(type(x))*8 - i))) 

defplotShifts(x):
    fig = plt.figure() # make a new figure
    ax = fig.add_axes([0.15, 0.2, 0.65, 0.7]) # add data axes
    origType = type(x)
    maxval = type(x)(-1)

    numrots = sizeof(type(x)) * 8
    vals = [rot(x, type(x)(i)) for i inrange(numrots)]

    print vals
    print maxval
    l, = ax.plot(range(numrots), vals, 'ro') # plot to data axes

    axcolor = 'lightgoldenrodyellow'
    inputax = fig.add_axes([0.15, 0.05, 0.65, 0.03], axisbg=axcolor)
    inputsl = Slider(inputax, 'Input', 0, maxval, valinit=0, valfmt="%d")

    defupdate(x):
        vals = [rot(origType(x), origType(i)) for i inrange(numrots)]
        l.set_ydata(vals)
        plt.draw()
    inputsl.on_changed(update)

    ax.set_ylim([-2,maxval +2]) # set ylim on data axes
    ax.set_xlim([-.5,numrots-1+.05]) # set xlim on data axesreturn inputsl

sldr = plotShifts(uint8(1))
plt.show()

Solution 2:

most likely because maxval =7 in this line

inputsl = Slider(inputax, 'Input', 0, maxval, valinit=0, valfmt="%d")