'listserializer' When Serializing A Queryset Using Django Rest Framework

I have a slightly complicated APIView which makes that I can't use a generic ListAPIView to return a queryset. But I can't seem to simply serialize a simple Django queryset using a

Solution 1:

Was running into the same problem as you did. I found a quick and simple fix for the error: Copy the serializer data to a new array and return that.

results = SomeModel.objects.all()

output_serializer = SomeModelSerializer(results, many=True)    
data = output_serializer.data[:]

return Response(data)

This works for me, hopefully for you as well.

Solution 2:

Below works for me using an as_view() url:

classListCreateMemberViewSet(generics.ListCreateAPIView):
        """
        API endpoint that allows multiple members to be created.
        """
        queryset = Member.objects.none()
        serializer_class = MemberSerializer

    defget_queryset(self):
         queryset = Member.objects.all()
         return queryset

    defcreate(self, request, *args, **kwargs):
        serializer = self.get_serializer(data=request.data, many=isinstance(request.data, list))
        serializer.is_valid(raise_exception=True)
        self.perform_create(serializer)
        results = Member.objects.all()
        output_serializer = MemberSerializer(results, many=True)
        data = output_serializer.data[:]
        return Response(data)

Solution 3:

The error is a result of trying to run a list on a serializer directly.

For example, this would raise the above exception:

results = Member.objects.all()
output_serializer = MemberSerializer(results, many=True)
all_results = list(output_serializer) # this line here
all_results += output_serializer  # or this line here

And this would not (difference is that we are listing output_serializer.data instead of output_serializer):

results = Member.objects.all()
output_serializer = MemberSerializer(results, many=True)
all_results = list(output_serializer.data)
all_results += output_serializer.data

I have the feeling that in the original question, the example code was not 100% matching the actual code.