Split String By Two Conditions - Wildcard

I need to split a string by a charcter plus a wildcard character: text1 = 'CompanyA-XYZ-257999_31.12.2000' text2 = 'CompanyB-XYZ-057999_31.12.2000' I want to split that string at

Solution 1:

Did you try this using re

import re
>>>re.findall("(.+XYZ)-(.+)",text1)
[('CompanyA-XYZ', '257999_31.12.2000')]

or

>>>re.findall("(.+)-(.+)",text1)
[('CompanyA-XYZ', '257999_31.12.2000')]

Solution 2:

You don't need a regex, you can split from the right using str.rsplit setting maxsplit to 1:

text1 = "CompanyA-XYZ-257999_31.12.2000"print(text1.rsplit("-",1))
['CompanyA-XYZ', '257999_31.12.2000']

text2 = "CompanyB-XYZ-057999_31.12.2000"print(text2.rsplit("-",1))
['CompanyB-XYZ', '057999_31.12.2000']

If you want them stored in variables just unpack:

comp, dte = text2.rsplit("-",1)
print(comp,dte)
('CompanyB-XYZ', '057999_31.12.2000')

Solution 3:

>>>text1 = "CompanyA-XYZ-257999_31.12.2000">>>text1[:-18]
'CompanyA-XYZ'

>>>text1[-17:]
'257999_31.12.2000'

Solution 4:

split by [-AnyNumber]

In[5]: importreIn[6]: re.split('-(?:[0-9])', text1)
Out[6]: ['CompanyA-XYZ', '57999_31.12.2000']In[7]: re.split('-(?:[0-9])', text2)
Out[7]: ['CompanyB-XYZ', '57999_31.12.2000']

Solution 5:

Using regex with a lookahead assertion:

>>>import re>>>text1 = "CompanyA-XYZ-257999_31.12.2000">>>text2 = "CompanyB-XYZ-057999_31.12.2000">>>re.split('-(?=\d)', text1)
['CompanyA-XYZ', '257999_31.12.2000']
>>>re.split('-(?=\d)', text2)
['CompanyB-XYZ', '057999_31.12.2000']