Flask-restplus / Route

I'm trying to use Flask-Restplus to make an api and document it with swagger. This is what I have so far and it works fine except I do not know how to add a root route. from flask

Solution 1:

I found very similar problem. I wanted make '/' route with custom page, and swagger doc on different path.

My first attempt (Not working)

from flask import Flask
from flask_restplus import Api

app = Flask(__name__)

api = Api(
    app= app,
    version='1.0',
    description='TEST API',
    doc='/docs/',
)

@app.route('/')defhello():
    return"Hello on my page"if __name__ == '__main__':
    app.run(debug=True, host='0.0.0.0', port=5000)

Page http://127.0.0.1:5000/ return 404 error

Working example

from flask import Flask
from flask_restplus import Api

app = Flask(__name__)

@app.route('/')defhello():
    return"Hello on my page"

api = Api(
    app= app,
    version='1.0',
    description='TEST API',
    doc='/docs/',
    default='mapi',
    default_label='Super API'
)

if __name__ == '__main__':
    app.run(debug=True, host='0.0.0.0', port=5000)

Tested on:

• Python 3.6.1
• Flask (0.12.1)
• flask-restplus (0.10.1)

Solution 2:

When you wrote ui=False you disabled the /rest/v1/ path.

In the next coming release (the 0.8.1 for the end of this week), you should be able to write:

from flask import Flask, Blueprint
from flask_restplus import Api, Resource

app = Flask('__name__')
blueprint = Blueprint('v1', __name__, url_prefix='/rest/v1')
api = Api(blueprint, doc='/apidoc/', version='1.0')

@blueprint.route('/', endpoint='rootres')defroot():
    return''

ns = api.namespace('test', description='desc')

@ns.route('/', endpoint='rootresource')classRootResource(Resource)
    defget(self):
        ...

app.register_blueprint(blueprint)

No need anymore to register a specific view for the documentation

For the `blueprint.route('/'), I think this is fixed by 0.8.1 too.

Note: register the blueprint later, after namespaces import/declaration.