Find Duplicate Elements In A List
I have a lists: nums = [1, 2, 3, 1, 5, 2, 7, 11] I am trying to make a function that returns how many times each number appears in the lists. Output may look like: 1 occurred 2 ti
Solution 1:
Counter is all you need
>>>from collections import Counter>>>Counter([1, 2, 3, 1, 5, 2, 7, 11])
Counter({1: 2, 2: 2, 3: 1, 5: 1, 7: 1, 11: 1})
Or you can just fix your code like this
def main():
original_nums = input("Enter integers between 1 and 100: ")
nums = [i for i in original_nums.split()]
my_dict = {}
for i in nums:
my_dict[i] = my_dict.get(i, 0) + 1
# or .setdefault(i, 0) instead of .get(i, 0)
# setdefault is generally faster
for i in my_dict:
print(i, 'occurs', my_dict[i], 'times')
if __name__ == '__main__':
main()
Runtime:
Enter integers between 1 and 100: 5 5 5 5 1 2 3 3 3
1 occurs 1 times
2 occurs 1 times
3 occurs 3 times
5 occurs 4 times
Solution 2:
You can simply use a collections.Counter
, which essentially does what you're trying to do internally:
>>>from collections import Counter>>>>>>nums = [1, 2, 3, 1, 5, 2, 7, 11]>>>>>>counts = Counter(nums)>>>>>>for t in counts.iteritems():...print'%d occured %d times' % t...
1 occured 2 times
2 occured 2 times
3 occured 1 times
5 occured 1 times
7 occured 1 times
11 occured 1 times
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